shapely - test if geometry items intersects in python list -


i have 1 list of data follows:

from shapely.geometry import box  data = [box(1,2,3,4), box(5,6,7,8), box(1,2,3,4)] codes = ['a','b','c']

the list 'data' has following elements:

a = box(1,2,3,4) b = box(5,6,7,8) c = box(1,2,3,4)

i have check if element intersect other elements. if intersects, should put in 1 tuple; , if not intersect should put in different tuple. expected result is:

result = [(a,c), (b)]

how it?

i tried as:

results = [] p,c in zip(data,codes):     x in data:         if p.intersects(x): ##.intersects return true if overlap else false             results.append(c) print results

keep dict of objects mapped a,b , c, set of matched objects , add single elements have no matches after new letter if not in our matched set possible combinations have been tested:

from shapely.geometry import box itertools import combinations  codes = ["a", "b", "c"] d = dict(zip(codes, data)) prev = codes[0] matched, out = set(), [] p1, p2 in combinations(codes, 2):     if d[p1].intersects(d[p2]):         out.append((p1, p2))         matched.update([p1, p2])     # when p1 new letter, have tried combs prev     # if prev not in matched did not intersect other    # add single tuple , add matched avoid dupes     elif p1 != prev , prev not in matched:         out.append(tuple(prev,))         matched.add(prev)     prev = p1 # catch last letter if p2 not in matched:     out.append(tuple(p2,)) print(out) [('a', 'c'), ('b',)]

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