c - The Funny string code -

the link question :https://www.hackerrank.com/challenges/funny-string

problem statement

suppose have string s has length n , indexed 0 n−1. string r reverse of string s. string s funny if condition |si−s(i−1)|=|ri−r(i−1)| true every 1 n−1.

(note: given string str, stri denotes ascii value of ith character (0-indexed) of str. |x| denotes absolute value of integer x)

#include <stdio.h> #include <string.h> #include <math.h> #include <stdlib.h>  int main() { char r[10000],s[10000]; int t[10],i,j,n,c1,c2,l,f; scanf("%d",&n); for(i=0;i<=(n-1);i++) {     t[i]=0;     c1=c2=0;f=0,l=0;     gets(s);     l=strlen(s);     for(j=0;j<l;j++)         r[j]=s[l-1-j];     for(j=1;j<l;j++)     {         c1=abs((int)(s[j])-(int)(s[j-1]));         c2=abs((int)(r[j])-(int)(r[j-1]));         if(c1==c2)             f=1;         else             f=0;     }     t[i]=f; } for(i=0;i<n;i++) {     if(t[i]==0)         printf("not funny\n");     else         printf("funny\n"); } return 0; } 

this code , required input/output

input

2
acxz
bcxz

output

funny
not funny

but getting different output can me in wrong code , worst output test case value 1.i not getting how giving value

you close.

the problem after entering number using scanf buffer left 1 \n character gets interpreted end of string, first input empty string (and no, it's not funny). before entering strings, need clean buffer:

scanf("%d",&n); 

should be:

scanf("%d",&n); while (getchar() != '\n'); 

and works:

2 acxz bcxz funny not funny 

of course, after figuring 1 out, hear advices people posted comment question. , enable warnings in compiler.