Convert json to struct using reflection in golang -

func deserialize(request *http.request,typ reflect.type) (interface{}, *httpnet.handlererror){      data,e:=ioutil.readall(request.body)     fmt.println(string(data))     if e !=nil{         return nil,&httpnet.handlererror{e,"could not read request",http.statusbadrequest}     }      v:=typ.elem()     payload:=reflect.new(v).elem().interface()      eaa:= json.newdecoder(request.body).decode(payload)      if e!=nil{         fmt.println(eaa.error())     }     fmt.println(payload)     fmt.println(reflect.valueof(payload)         )     return payload,nil  } 

to call it:

r,_:= deserialize(request,reflect.typeof(&testdata{})) 

it not throw errors , looks valid operation me , result empty structure of expecting type.

whats problem that?

the problem passing non pointer instance of type:

payload:=reflect.new(v).elem().interface() 

means "allocate new pointer type, take value of it, , extract interface{}.

you should keep at:

payload:=reflect.new(v).interface() 

btw it's redundant passing type of pointer, extracting elem(), allocating pointer. this:

if type.kind() == reflect.ptr {    typ = typ.elem() }  payload := reflect.new(typ).interface() 

then can pass both pointers , non pointers function.

edit: working playground example: http://play.golang.org/p/tpafxcpiu5