php - Select all fields from a table where a field in another table with an ID is equal to a string -


i have 2 tables:

ads: fields id, a, b , c:

+----+---+-------+------+ | id | | b     | c    | +----+---+-------+------+ |  1 | x | y     | z    | |  2 | c | v     | b    | |  3 | n | n     | m    | +----+---+-------+------+

requests: fields id, adid, , status:

+----+------+----------+ | id | adid |  status  | +----+------+----------+ |  3 |    1 | pending  | |  4 |    2 | approved | |  5 |    3 | pending  | +----+------+----------+

id (from ads) = adid (from requests).

now, want records ads adid's (from requests) status equals pending. adid here the value id ads.

so, above tables, result i'd id 1 , 3 ads:

+----+---+---+---+ | id | | b | c | +----+---+---+---+ |  1 | x | y | z | |  3 | n | n | m | +----+---+---+---+

this closest i've got far, doesn't work because can select 1 row - whereas need select many: 

select * ads id = (select adid requests status = 'pending')

this might not make sense - please ask if haven't explained - i'll as possible :)

use in in place of =:

select *  ads  id in (select adid requests status = 'pending')

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