xml - Python Resize Multiple images ask user to continue -


i'm trying make script resize multiple or single image based on data pulled xml. question if have multiple images how can print out qusetion "there more 1 image wish resize image 2 also?... maybe " liek resize image 3 ?"

my script far follow,the problem taht resizez images @ start :

import os, glob import sys  import xml.etree.celementtree et  import re  pil import image  pathnow ='c:\\'    items = [] textpath = [] imgpath = []  attribvalue = []  #append system argument list later use  item in sys.argv:      items.append(item)  #change path directory  newpath = pathnow + items[1]   os.chdir(newpath)  #end   #get first agrument doc ref item in items:     docxml = items[2]  #search file  file in glob.glob(docxml + ".xml"):      tree = et.parse(file)      rootfile = tree.getroot()      rootchild in rootfile.iter('textelement'):         if "svg" or "pdf" in rootchild.text:             try:                 textpath = re.search('svg="(.+?)"', str(rootchild.text)).group(1)                 attribvalue.append(rootchild.get('elementid'))                 imgpath.append(textpath)             except:                 continue  image in imgpath:     new_img_path = image[:-4] + '.png'     new_image = image.open(new_img_path)     new_size=int(sys.argv[3]), int(sys.argv[4])     try:         new_image.thumbnail(new_size,  image.antialias)         new_image.save(new_img_path, 'png')     except ioerror:         print("cannot resize picture '%s'" % new_img_path)     finally:         new_image.close()         print("done resizeing image: %s " % new_img_path)   

thank in advance.

zapo

change final loop to:

for idx, image in enumerate(imgpath):     #img resizing goes here      count_remaining = len(imgpath) - (idx+1)     if count_remaining > 0:         print("there {} images left resize.".format(count_remaining))         response = input("resize image #{}? (y/n)".format(idx+2))         #use `raw_input` in place of `input` python 2.7 , below         if response.lower() != "y":             break 

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