SQL Oracle | How would I select a substring where it begins with a certain letter and ends with a certain symbol? -


if had this: 

name        eyes==id==hair jon         brown==f9182==red may         blue==f10100==brown bill        hazel/green==f123==brown

...and wanted create new id column id alone, , know everyone's id starts 'f' , end @ '=' how select substring compact column , take id out?

ex. want end product

name        eyes==id==hair               id jon         brown==f9182==red            f9182 may         blue==f10100==brown          f10100 bill        hazel/green==f123==brown     f123

if can't make end @ '=' there way trim rest of content isn't part of id after selecting it?

you can use regular expression:

regexp_substr('hazel/green==f123==brown','(==f.+?==)')

extracts '==f123==', trim =:

ltrim(rtrim(regexp_substr('hazel/green==f123==brown','(==f.+?==)'), '='), '=')

if oracle supported lookahead/lookbehind easier...

edit:

base on @erkanhaspulat's query don't need ltrim/rtrim can specify return first capture group (i forget that). safe should change regex not greedy:

regexp_substr('hazel/green==f123==brown==iii','==(.+?)==', 1, 1, null, 1)

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