vb6 - Converting VERY large number to a hex string - 


public function mymod(a double, b double) double mymod = - int(a / b) * b end function

this code doesn't work doesn't correctly show remainder able calculate hex.

correct : 10009335357561071 / 16 = 62558345984756.69 vb6 mymod returns 0 instead of valid remainder.

i have been unable figure out how convert such large value hex string?

i able code myself. because of vb6 limitations of size of number, had go in different ways. needed able covert large whole numbers binary , hexadecimal.

this code, there 3 functions can use. 1) decimal 2 hex 2) binary hex 3) decimal 2 binary

the code works , gives me correct returns large numbers.

public function dec2hex(dec string) string  dec2hex = binary2hex(dec2bin(dec)) end function  public function binary2hex(binary string, optional pos long = 0) string  dim tic long  dim sz long  dim x long  dim z long  dim @ long  dim hx long  dim hxb string  dim xstart long  dim xstop long   hxb = vbnullstring  if instrb(binary, " ") <> 0 binary = replace(binary, " ", "")  sz = len(binary)   xstart = sz  xstop = xstart - 3    @ = 0  hx = 0  if xstop < 1 xstop = 1  x = xstart xstop step -1    @ = @ + 1    if ascb(mid$(binary, x, 1)) = 49      select case @         case 1: hx = hx + 1         case 2: hx = hx + 2         case 3: hx = hx + 4         case 4: hx = hx + 8      end select    end if  next x  hxb = digit2hex(cstr(hx)) + hxb  if x <= 1 exit  xstart = x  xstop = xstart - 3  loop  binary2hex = hxb end function  private function digit2hex(digit string) string  select case digit    case "0": digit2hex = "0"    case "1": digit2hex = "1"    case "2": digit2hex = "2"    case "3": digit2hex = "3"    case "4": digit2hex = "4"    case "5": digit2hex = "5"    case "6": digit2hex = "6"    case "7": digit2hex = "7"    case "8": digit2hex = "8"    case "9": digit2hex = "9"    case "10": digit2hex = "a"    case "11": digit2hex = "b"    case "12": digit2hex = "c"    case "13": digit2hex = "d"    case "14": digit2hex = "e"    case "15": digit2hex = "f"    case else: digit2hex = vbnullstring  end select end function  public function dec2bin(dec string) string  dim bin string  dim var variant  dim p long  dim tmp string   bin = vbnullstring  tmp = dec    bin = iif(iseven(tmp), "0", "1") + bin   var = cdec(tmp)   var = var / 2   tmp = cstr(var)   p = instr(tmp, ".")   if p > 0 tmp = mid(tmp, 1, p - 1)   if len(tmp) = 1    if clng(tmp) = 0 exit   end if  loop  dec2bin = bin end function  public function iseven(dec string) boolean  dim oe long  dim mydec variant   oe = clng(right$(cstr(dec), 1))  iseven = (oe = 0 or oe = 2 or oe = 4 or oe = 6 or oe = 8)  end function

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