How should I add a stationary progress bar to a C++ program that produces terminal output (in Linux)? -


i have existing program contains loop on files. various things, providing lots of terminal output. want have overall progress bar remains stationary on same line @ bottom of terminal while of output file operations printed above it. how should try this?

edit: so, clear, i'm trying address display problems inherent in bit following:

#include <unistd.h> #include <iostream> #include <string>  using namespace std;  int main(){   (int = 0; <= 100; ++i){     std::cout << "processing file number " << << "\n";     string progress = "[" + string(i, '*') + string(100-i, ' ') + "]";     cout << "\r" << progress << flush;     usleep(10000);   } }

the portable way of moving cursor around know of using \r move beginning of line. mention output stuff above progress. fortunately, in luck since you're on linux , can use terminal escape codes move around terminal freely. @ example:

#include <unistd.h> #include <iostream> #include <string>  using namespace std;  int main() {   cout << endl;   (int i=0; <= 100; ++i)   {     string progress = "[" + string(i, '*') + string(100-i, ' ') + "]";     cout << "\r\033[f" << << "\n" << progress << flush;     usleep(10000);   } }

here, added ability print progress value above progress bar moving beginning of line using \r , 1 line using escape code \033[f before printing. then, printed 1 line, moved down 1 line \n , re-printed progress.

you can go further , move cursor x,y position in terminal before printing. use escape code \033[y;xf before output.

for list of escape codes, check out wikipedia: https://en.wikipedia.org/wiki/ansi_escape_code#csi_codes

so, possible achive behavior without using additional libs ncurses, maybe want if intend create more gui-like experience.

fixing attempt:

void print_progress_bar(int percentage){   string progress = "[" + string(percentage, '*') + string(100 - percentage, ' ') + "]";   cout << progress << "\r\033[f\033[f\033[f" << flush; }  int main(){   cout << endl;   (int i=0; <= 100; ++i){     std::cout << "processing file number " << << "\n";     std::cout << "    doing thing file number " << << "\n";     std::cout << "    doing thing file number " << << "\n";     print_progress_bar(i);     usleep(10000);   }   cout << endl;   cout << endl;   cout << endl;   cout << endl; }

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