spring + Embedded jetty + <web-app> how to create context -
there maven-project, /web-inf/web.xml :
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/xmlschema-instance" xsi:schemalocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <servlet> <servlet-name>basewebapp</servlet-name> <servlet-class>org.springframework.web.servlet.dispatcherservlet</servlet-class> <init-param> <param-name>contextconfiglocation</param-name> <param-value>/web-inf/applicationcontext.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>basewebapp</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping>
and applicationcontext.xml :
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/xmlschema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context" xmlns:mvc="http://www.springframework.org/schema/mvc" xsi:schemalocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd"> <import resource="classpath:datasource.xml"/> <mvc:annotation-driven/> <context:component-scan base-package="com.blogspot.permgen.webapp"/> <mvc:resources mapping="/resources/**" location="/resources/"/> <bean class="org.springframework.web.servlet.view.internalresourceviewresolver" p:prefix="/web-inf/pages/" p:suffix=".jsp"/> </beans>
the controller based oh annotations.
when launched mvn -djetty.port=9999 jetty:run applicaton starts well. decided initialize jetty in code, failed create context it. here main class:
public class appmain { public static void main(string[] args) throws exception { servletcontexthandler sch = new servletcontexthandler(); /*here must context initialization ... */ server jetty = new server(9999); jetty.sethandler(sch); jetty.start(); } }
so question is: how init context jetty web.xml ?
possible @ all, or have parse somehow using of spring?
if want use web.xml configure context, don't use servletcontexthandler, instead use webappcontext, derived servletcontexthander , adds ability use web.xml configure itself.
here example: https://www.eclipse.org/jetty/documentation/current/embedded-examples.html#embedded-one-webapp
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