python - Split by a word (case insensitive) -


if want take

"hi, name foo bar"

and split on "foo", , have split case insensitive (split on of "foo", "foo", "foo", etc), should do? keep in mind although have split case insensitive, want maintain case sensitivity of rest of string.

so if have:

test = "hi, name foo bar"  print test.split('foo')  print test.upper().split("foo")

i 

['hi, name ', ' bar'] ['hi, name ', ' bar']

respectively.

but want is:

['hi, name ', ' bar']

every time. goal maintain case sensitivity of original string, except splitting on.

so if test string was:

"hi name foo bar"

my desired result be:

['hi name ', ' bar']

you can use re.split function re.ignorecase flag (or re.i short):

>>> import re >>> test = "hi name foo bar" >>> re.split("foo", test, flags=re.ignorecase) ['hi name ', ' bar'] >>>

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