How to convert a string with some lines to a list that every cell contains one line in Python? -


i have variable string string type this:

string = """first second third ..."""

i want add every line separate cell of list, because variable size change can't use this:

temp=[] temp.append(s[0:5]) ....

and didn't find helpful function separate lines me.

there built-in function this: str.split. returns list of string containing whole passed string cut accordingly given character. example:

>>> "foo bar foobar".split(' ') ['foo', 'bar', 'foobar']

here, want use space separator. in case, want have every different line in single string. so, separator new line character, in python represente \n character. so, have is:

lines_list = s.split('\n')

but, depends on os you're using program: on unix based systems, work. but, windows has chosen use carriage return (\r in python) and line feed (n) lines separator. so, if apply previous code on windows system, you'll have list looks ['foo\r', 'bar\r', 'foobar\r']. problem presence of carriage returns may cause issues, have remove them, doing example this:

lines_list = [line.replace('\r', '') line in lines_list]

basically, line of code create new list (using comprehension list) contains elements of lines_list, \r has been replaced by... nothing, has been deleted.


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