c - Combine or merge 2 array with loop or function -


i'm new c world. i'm using visual 2010. need create array 2 other arrays, or function merge them; come php i'm sorry if stupid. tested loop without success..

a real example helpful:

int arraya[5] = {3,2,1,4,5}  int arrayb[5] = {6,3,1,2,9}

and printed expected output of third arrayc should :

arrayc { [3][6] [2][3] [2][1] [4][2] [5][9] }

a straightforward approach can following way

#include <stdio.h>  #define n   5  int main( void ) {     int a[n] = { 3, 2, 2, 4, 5 };      int b[n] = { 6, 3, 1, 2, 9 };     int c[n][2];      ( size_t = 0; < n; i++ )     {         c[i][0] = a[i]; c[i][1] = b[i];     }      ( size_t = 0; < n; i++ ) printf( "%d, %d\n", c[i][0], c[i][1] );       return 0; }

the program output is

3, 6 2, 3 2, 1 4, 2 5, 9

if want write function merge arrays of size can like

#include <stdio.h> #include <stdlib.h>  #define n   5  int ** merge( int *a, int *b, size_t n ) {     int **c = malloc( n * sizeof( int * ) );      if ( c != null )     {         size_t = 0;         ( ; < n && ( c[i] = malloc( 2 * sizeof( int ) ) ); i++ )         {             c[i][0] = a[i]; c[i][1] = b[i];         }          if ( != n )         {             while ( i-- ) free( c[i] );             free( c );             c = null;         }     }      return c; }     int main( void ) {     int a[n] = { 3, 2, 2, 4, 5 };      int b[n] = { 6, 3, 1, 2, 9 };     int **c;      c = merge( a, b, n );      if ( c != null )     {         ( size_t = 0; < n; i++ ) printf( "%d, %d\n", c[i][0], c[i][1] );          ( size_t = 0; < n; i++ ) free( c[i] );         free( c );     }      return 0; }

the program output same shown above.


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