javascript - How to integrate Jquery with PHP -


when mouse on html button didn't happen anything, expect if mouse on button should show javascript working fine. there way achieve this. new javascript code may wrong.

<!doctype html>     <html>     <head>         <title>javascript</title>         <script type="text/javascript">             $(document).ready(function(e) {                  $(".carts").mouseover(function(){                     $(".minicart").css("display","block");                 });                  $(".carts").mouseleave(function(e) {                     $(".minicart").css("display","none");                  });             }     </script>      </head>     <body>      <button class="carts"> add </button>     <div style="width:400px;position:absolute;top: 34px;right: 166px;z-index: 99999; background-color:#ffffff; display:none" class="minicart">        <?php     $var = 7;      if($var == 7)     {         echo "javascript works fine ";     }     else     {         echo "didn't work";     }       ?>      </div>     </body>     </html> 

<html>     <head></head> <body>      <button class="carts"> add </button>      <div style="width:400px;position:absolute;top: 34px;right: 166px;z-index: 99999; background-color:#ffffff; display:none; border:1px solid black" class="minicart"></div>      <!-- import jquery google hosted libraries         or can download latest jquery version         , use project      -->     <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>      <script>          $(document).ready(function(){             // bind events             $(".carts").mouseover(function(){                 $(".minicart").css("display","block");              });              $(".carts").mouseleave(function(e) {                $(".minicart").css("display","none");              });         });      </script>  <?php     $var = 7;      if($var == 7)     {         echo "javascript works fine ";     }     else     {         echo "didn't work";     }       ?> </body> </html> 

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