c - How to store result of type char in pointer? -


i want store result of type char in pointer i'm passing argument of function. this:

#include<stdio.h> void try(char *); int main() {     char *result;     try(result);     printf("%s",result);     return 0; } void try(char *result) {     result="try this"; }

but i'm getting result : (null)

could tell me what's wrong here?

also way (no dynamic memory):

#include<stdio.h> void try(char *); int main() {     char result[100] = {0};     try(result);     printf("%s",result);     return 0; } void try(char *result) {     strcpy(result,"try this"); }

note: when got null, doesn't mean - had undefined behaviour there - because result not initialized. guess invoked ub before trying print result, namely when passed try. because copy made in method of pointer, try read value of original pointer - reading uninitialized variables undefined in c. hence initialize variables in c.


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