Django admin with inlines, 1 model with 2 foreigns keys to 2 different models -


i have 3 models total. main model has 2 foreign keys 2 different models. relationships setup many-to-one. when try customize admin, cannot allow me edit main character model , have 2 inlines (universe , series) show up.

what simplest way? there seams ambiguity since 2 foreign fields throwing off. have scoured documentation must have missed something; have gotten more complex many-to-many working in admin, bit odd.

here models:

class characterseries(models.model):     name = models.charfield(max_length=200)      def __unicode__(self):         return self.name   class characteruniverse(models.model):     name = models.charfield(max_length=200)       def __unicode__(self):         return self.name   class character(models.model):     name = models.charfield(max_length=200)      rating = models.decimalfield(max_digits=3, decimal_places=1)     universe = models.foreignkey(characteruniverse)         series = models.foreignkey(characterseries)      def __unicode__(self):         return self.name 

here admin:

from django.contrib import admin .models import character, characteruniverse, characterseries  # register models here.   class seriesinline(admin.tabularinline):     model = character  class universeinline(admin.tabularinline):     model = character  class characterdmin(admin.modeladmin):     inlines = [         universeinline,         seriesinline,    ]  admin.site.register(character, characteradmin)    

update

the code posted earlier wrong! didn't read models carefully. sorry that.

if want create characterseries , characteruniverse while create/edit character, this:

from django.contrib import admin .models import character, characteruniverse, characterseries  # no need define `modeladmin` classes  admin.site.register(character) admin.site.register(characteruniverse) admin.site.register(characterseries) 

the code above give + (plus) sign after universe , series fields. create characteruniverse , characterseries objects on fly.


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