mysql - How to display fetched result inside php form? -


i php mysql beginner! trying id (primary key) value of row , update corresponding values in database. search results working perfecting , getting redirected update form page, in wanted display fetched result, can edit result , update values.

my php

<?php require_once 'db_alternate2.php'; session_start();  try{ $conn = new pdo("mysql:host=$host;dbname=$dbname", $username, $password); if( isset($_get['edit']) ) { $id = $_get['edit'];   $res= "select * staff_db staff_id='$id'";  $r = $conn->query($res); $r->setfetchmode(pdo::fetch_assoc); }  if( isset($_post['new_staf_id']) && isset($_post['new_staf_name']) && isset($_post['new_staf_acc']) && isset($_post['new_staf_bnkaddrs']) ) {  $staf_id = $_post['new_staf_id'];  $staf_name = $_post['new_staf_name'];  $staf_acc = $_post['new_staf_acc'];  $staf_bnkaddrs = $_post['new_staf_bnkaddrs'];  $sql = $conn->prepare("update staff_db set staff_id='$staf_id' staff_name='$staf_name' staff_acc='$staf_acc' staff_bnkaddrs='$staf_bnkaddrs' sl_no ='$id'");  $sql->execute();  $result1 = $sql->fetch(pdo::fetch_assoc);   echo "<meta http-equiv='refresh' content='0;url=staff_update.php'>";  }  } catch (pdoexception $pe) {  die("could not connect database $dbname :" . $pe->getmessage());  }  ?> .

my html

  <form class="" style="right:10px !important;" action="staff_db.php" method="post">      <div class="main-left" style="width:38% !important; margin-left:100px;">       <p>staff id:</p> <input type="text" name="staf_id" value="______"/>       <p>name:</p> <input type="text" name="staf_name" value="______"/>     </div>      <div class="main-right" style="width:38% !important; margin-right:100px;">       <p>account no:</p> <input type="text" name="staf_acc" value="______"/>       <p>bank address:</p> <input type="text" name="staf_bnkaddrs" value="______"/>     </div>      <div class="bottom-centre" style="padding-top:50px; ">       <input class="submit" type="submit" value="update"/>     </div>    </form>

i know simple question, guide me here! how display pdo fetched results inside value="______" of form.

thanks in advance!

just few modifications in code

if( isset($_get['edit']) )  {  $id = $_get['edit'];    $res= "select * staff_db staff_id='$id'";    $r = $conn->query($res);  $r->setfetchmode(pdo::fetch_assoc);  $result = $r->fetch();  }

and few modification in form put value

<input type="text" name="staf_name" value=<?php echo $result["staff_name"]; ?>/>


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