c++ - How convert unsigned int to unsigned char array -


i need extract bytes using bitwise & operator. 0xff hexadecimal mask extract 1 byte. 2 bytes, code working correctly:

#include <stdio.h>  int main() {     unsigned int = 0x7ee;     unsigned char c[2];      c[0] = & 0xff;     c[1] = (i>>8) & 0xff;      printf("c[0] = %x \n", c[0]);     printf("c[1] = %x \n", c[1]);       return 0; }

output:

c[0] = ee; c[1] = 7;

what should 4 bytes work correctly?

unsigned int = 0x557e89f3; unsigned char c[4];

my code:

unsigned char c[4];          c[0] = & 0xff;          c[1] = (i>>8) & 0xff;          c[2] = (i>>16) & 0xff;          c[3] = (i>>24) & 0xff;          printf("c[0] = %x \n", c[0]);          printf("c[1] = %x \n", c[1]);          printf("c[2] = %x \n", c[2]);          printf("c[3] = %x \n", c[3]); 

#include <stdio.h>  int main() {     unsigned int = 0x557e89f3;     unsigned char c[4];      c[0] = & 0xff;     c[1] = (i>>8) & 0xff;     c[2] = (i>>16) & 0xff;     c[3] = (i>>24) & 0xff;      printf("c[0] = %x \n", c[0]);     printf("c[1] = %x \n", c[1]);     printf("c[2] = %x \n", c[2]);     printf("c[3] = %x \n", c[3]);       return 0; }

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