In Oracle SQL, how can I display a blank row between every unique row? -


suppose have simple query like:

select employee, item_type, count(item_type)   hr_database

so output may like

 bob  mugs  4   bob  pencils 10   cat  mugs  2   cat  paperclips  7   sal  mugs  11

but readability, want put blank row between each user in output(i.e readability), :

 bob  mugs  4   bob  pencils 10    cat  mugs  2   cat  paperclips  7    sal  mugs  11

is there way in oracle sql ? far, i found link doesn't match need . i'm thinking use in query?

thanks !

you can in database, type of processing should done @ application layer.

but, kind of amusing trick figure out how in database, , specific question:

with e (       select employee, item_type, count(item_type) cnt       hr_database       group employee, item_type      ) select (case when cnt not null employee end) employee,        item_type, cnt (select employee, item_type, cnt, 1 x e union       select distinct employee, null, null, 2 x e      ) e order e.employee, x;

i emphasize, though, amusement , perhaps understanding better how sql works. in real world, type of work @ application layer.

a summary of how works. union all brings in 1 additional row each employee. x priority sorting -- because have sort result set proper ordering. case statement needed prevent employee being in first column. cnt should never null valid rows.


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