loops - How to repeat this statement in R probably using apply() -


it might seem silly question how repeat line 152 times , not use loop,since later not efficient larger data sets:

reviews = as.vector(t(mydata)[,1])

mydata row in data.frame , reviews array of characters, [,1] first row

the output matrix or worst case data.frame.

i tried this, did not work :

testing = apply(mydata, 1, function(x) {as.vector(t(mydata[,x]))}) error in t(mydata)[, x] : subscript out of bounds

thanks.

edit: quick data sample:

> reviews = as.vector(t(mydata)[,1]) > class(reviews) [1] "character" > length(reviews) [1] 14 > reviews [1] "i involuntarily"                                                                    [2] "i in transit"                                                                                    [3] "my initial flight"                                                                              [4] "that still left"                                                                                            [5] "after disembarking"                                                                     [6] "customs , proceed gate."                                                                                                                                                                         [7] "i arrived"                                                                                                                                      [8] "when boarding pass scanned"                          [9] "no reason given bump."                                                                                                                                                                       [10] "the ua gate staff" [11] "i boarded air canada."                                                                                                                     [12] "after arriving"                                                                                   [13] "i spent 5 hours"                                                                                                            [14] na

mydata data.frame:

> class(mydata)  [1] "data.frame"  > length(mydata[,1])  [1] 152  > mydata[,1]  [1] involuntarily... .  [2] first time... .   ...  ...                                                                                       152 levels: first time . ...

i have 30.000 of these, want start small, 152 of paragraphs split in individual sentence , put data.frame. each row in data.frame has 5-15 sentences.

i want to able access each row array since need perform action on each row of data.frame

packages used: plyr, sentiment(downloaded here , installed manually)

edit 2:

 dput(mydata[1:6, 1:6])  structure(list(v1 = structure(c(70l, 41l, 94l, 114l, 47l, 49l),   .label = c(" air canada",   "their service",   "hours de-icing",   "have flown ba",   "my booking",   "if video screen",   "frankfurt flights",   "and 150 lines of text data",

here's recommended way ask question, focusing on fact actual data big, complicated, or private share.

question: how apply function on each row of data.frame?

my data:

# make data s <- "lorem ipsum dolor sit amet, consectetur adipiscing elit, sed eiusmod tempor incididunt ut labore et dolore magna aliqua." mydata <- as.data.frame(matrix(strsplit(s, '\\s')[[1]][1:18], nrow=3, ncol=6), stringsasfactors=false) mydata ##      v1          v2         v3      v4         v5     v6 ## 1 lorem         sit adipiscing      incididunt     et ## 2 ipsum       amet,      elit, eiusmod         ut dolore ## 3 dolor consectetur        sed  tempor     labore  magna

if have data can use directly, has been suggested multiple times in comments, use of dput helpful:

mydata <- structure(list(v1 = c("lorem", "ipsum", "dolor"),v2 = c("sit", "amet,", "consectetur"), v3 = c("adipiscing", "elit,", "sed"),      v4 = c("do", "eiusmod", "tempor"), v5 = c("incididunt", "ut", "labore"), v6 = c("et", "dolore", "magna")), .names = c("v1",      "v2", "v3", "v4", "v5", "v6"), row.names = c(na, -3l), class = "data.frame")

in either order, state (i) trying do, , (ii) have tried , how not working.

my desired output:

converting row vector ... confusing. row vector, don't know trying do. so, i'll come short point: want words on each row in reverse alphabetical order, perhaps this:

##       v1    v2         v3      v4     v5          v6 ## 1    sit lorem incididunt      et      adipiscing ## 2     ut ipsum      elit, eiusmod dolore       amet, ## 3 tempor   sed      magna  labore  dolor consectetur

this time show code you've tried, errors you've encountered, and/or how unerring output not intended.

answer, generically:

several ways each row:

  1. use apply, though breaks if have numeric , character intermingled. if try this, you'll see output transpose of may think, in case you'll need wrap (and of other *apply-based suggestions here) t(...). it's little confusing, it's necessary here. oh, , they'll matrix class can converted data.frame if needed.

    ret <- apply(mydata, 1, function(r) {     do_something(r) })

  2. use sapply or lapply on row indices. note these returning lists or vectors of results, you'll need convert whatever format need.

    ret <- sapply(1:nrow(mydata), function(i) {     do_something(mydata[i,]) })  # if need keep each row's results rather encapsulated, use 1 of following: ret <- sapply(1:nrow(mydata), function(i) {     do_something(mydata[i,]) }, simplify=false)  ret <- lapply(1:nrow(mydata), function(i) {     do_something(mydata[i,]) })

  3. use foreach , iterators.

    library(foreach) library(iterators) ret <- foreach(df=iter(mydata, by='row'), .combine=rbind) %do% {     do_something(df) # 1 row of mydata time }

in case of (contrived) question, here several ways it:

as.data.frame(t(apply(mydata, 1, function(r) sort(r, decreasing=true)))) ##       v1    v2         v3      v4     v5          v6 ## 1    sit lorem incididunt      et      adipiscing ## 2     ut ipsum      elit, eiusmod dolore       amet, ## 3 tempor   sed      magna  labore  dolor consectetur  as.data.frame(t(sapply(1:nrow(mydata), function(i) sort(mydata[i,], decreasing=true)))) ## same output  library(foreach) library(iterators) ## notice use of as.character(...), perhaps still blasphemy ## structure of data.frame ret <- foreach(df=iter(mydata, by='row'), .combine=rbind) %do% {     sort(as.character(df), decreasing=true) } ret ##          [,1]     [,2]    [,3]         [,4]      [,5]     [,6]          ## result.1 "sit"    "lorem" "incididunt" "et"      "do"     "adipiscing"  ## result.2 "ut"     "ipsum" "elit,"      "eiusmod" "dolore" "amet,"       ## result.3 "tempor" "sed"   "magna"      "labore"  "dolor"  "consectetur"

Comments

Post a Comment

Popular posts from this blog

c# - Validate object ID from GET to POST -

i have method allows user access comment have made on site. have post method lets them update comment. my normal solution send entire comment model through, let them update it, update on database when post back. involve sending commentid through in hiddenfor , can manipulated. how can verify commentid sent in get method same i'm getting in post , not able alter comment wish? how can verify commentid sent in method same i'm getting in post? basically have validate following things in post - user logged-in user. authenticated users post comments. commentid in post , should valid commentid , should present in database. userid associated logged-in user should same userid associated comment . comment should contain userid column, can check @ time of update. to make sure update happens comment has been sent in get - hold commentid in session , in post action compare commentid value in session .
Read more

node.js - Custom Model Validator SailsJS -

when using custom model validator checks record within model. return within spread doesn't seem end control flow. //post.js model /** * custom validator **/ types: { isuservalid: function(user_id) { var promise = require('bluebird'); promise.all([ user.findone({id: user_id}) ]) .spread(function(user) { console.log(user); if (user === null || user === undefined) { console.log('failed'); return false; }else{ console.log('passed'); return true; } }); } }, my response standard validation failed response. { "error": "e_validation", "status": 400, "summary": "1 attribute invalid", "model": "post", "invalidattributes": { "owner": [ { "rule": "isuservalid", ...
Read more

php - Find a regex to take part of Email -

i have following emails need extract part from: bestellnummer xxx: 1 von xxx, 1er pack ------------- anfang der nachricht ------------- foo bar baz foo bar baz // <<<<< need text here ------------- ende der nachricht ------------- ------------- anfang der nachricht ------------- foo bar baz foo bar baz ------------- ende der nachricht ------------- there 0 unlimited occurences of ------------- anfang der nachricht ------------- ------------- ende der nachricht ------------- and i'm able extract first part regex: $re = "/------------- .*? -------------.?(.*?).?------------- .*? -------------/s"; but, i'm quite new on learning regex, i'm pretty sure there must better regex extract part (foo bar baz foo bar baz) of text between ------------- anfang der nachricht ------------- ------------- ende der nachricht ------------- as can in different languages, i'm using .? to match between hyphens. i...
Read more