fortran - Using Floor and Int in a computation -


i using calculation locate base pixel. seems me 2 calculations , j equivalent (i.e. i==j true) when tried few examples. true?

i = (int ((x - xmin) / a)) + 1 j = (floor ((x - xmin) / a)) + 1

in addition above, following may give different result , j (i.e. there exist situations i/=j). 

i = (nint ((x - xmin) / a)) + 1 j = (ceiling ((x - xmin) / a)) + 1

it true in scenario

when value stored in ix 'int' function, ignore float values , consider whole number before decimal point. in case of floor, convert nearest lower whole number.

the difference is: in first case, floats ignored, , in second case- entire number converted.

ultimately, both results same. (only in scenario) recommended use right functions right calculation.


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