java - how to define path to superpom? -


any maven experts out there? inherited huge maven project , trying compile. not getting far. go highest level pom.xml can find, located in trunk directory, 1 level down main project. issue command "mvn validate". following error:

[info] scanning projects... downloading: http://repo1.maven.org/maven2/com/mycompany/neto/vsd/vsd-superpom/1.1.0/vsd-superpom-1.1.0.pom [info] unable find resource 'com.mycompany.neto.vsd:vsd-superpom:pom:1.1.0' in repository central (http://repo1.maven.org/maven2)

i noticed vsd-superpom folder @ same level main project i'm guessing main project needs point somewhere? looking @ pom.xml see

<parent>     <groupid>com.mycompany.neto.vsd</groupid>     <artifactid>vsd-superpom</artifactid>     <version>1.1.0</version> </parent>

where put vsd-superpom folder found? don't understand why tries download it. don't see in pom.xml tells that.

apache maven has 2 level strategy resolve , distribute files, call artifacts. first level called local repository, artifact cache on system, default located @ ${user.home}/.m2/repository. when executing maven, it'll first in local cache artifacts. if artifact cannot found here, maven access remote repositories find artifact. once found stored local repository, it's available current , future usage.

see apache maven install plugin documentation

so if super pom independent of rest of project can invoke mvn install super pom folder placed local repository. solve problem.

usually top-level project pom defines project dependencies , should enough invoke mvn verify | compile | ...

if top-level pom depends on super pom have install super pom first (or define pom contains submodules super pom , rest of project)


Comments

Post a Comment

Popular posts from this blog

c# - Validate object ID from GET to POST -

i have method allows user access comment have made on site. have post method lets them update comment. my normal solution send entire comment model through, let them update it, update on database when post back. involve sending commentid through in hiddenfor , can manipulated. how can verify commentid sent in get method same i'm getting in post , not able alter comment wish? how can verify commentid sent in method same i'm getting in post? basically have validate following things in post - user logged-in user. authenticated users post comments. commentid in post , should valid commentid , should present in database. userid associated logged-in user should same userid associated comment . comment should contain userid column, can check @ time of update. to make sure update happens comment has been sent in get - hold commentid in session , in post action compare commentid value in session .
Read more

node.js - Custom Model Validator SailsJS -

when using custom model validator checks record within model. return within spread doesn't seem end control flow. //post.js model /** * custom validator **/ types: { isuservalid: function(user_id) { var promise = require('bluebird'); promise.all([ user.findone({id: user_id}) ]) .spread(function(user) { console.log(user); if (user === null || user === undefined) { console.log('failed'); return false; }else{ console.log('passed'); return true; } }); } }, my response standard validation failed response. { "error": "e_validation", "status": 400, "summary": "1 attribute invalid", "model": "post", "invalidattributes": { "owner": [ { "rule": "isuservalid", ...
Read more

php - Find a regex to take part of Email -

i have following emails need extract part from: bestellnummer xxx: 1 von xxx, 1er pack ------------- anfang der nachricht ------------- foo bar baz foo bar baz // <<<<< need text here ------------- ende der nachricht ------------- ------------- anfang der nachricht ------------- foo bar baz foo bar baz ------------- ende der nachricht ------------- there 0 unlimited occurences of ------------- anfang der nachricht ------------- ------------- ende der nachricht ------------- and i'm able extract first part regex: $re = "/------------- .*? -------------.?(.*?).?------------- .*? -------------/s"; but, i'm quite new on learning regex, i'm pretty sure there must better regex extract part (foo bar baz foo bar baz) of text between ------------- anfang der nachricht ------------- ------------- ende der nachricht ------------- as can in different languages, i'm using .? to match between hyphens. i...
Read more