bash - sed replace with eval -


what want do

replace: '1000' with: (a random number) shuf -i 500-1500 -n 1

shuf .. shall exectued every occurence of 1000

what i've tried

sed -i 's/1000/$(shuf -i 500-1500 -n 1)/g'

but takes eval string

it happens because single quotes escape meaning of $ , command substitution not occurring.

solution use double quotes

sed -i "s/1000/$(shuf -i 500-1500 -n 1)/g"

to replace each occurrence different values shuf, can loop on file using basic while , replace string as

while read line     echo "$line" | sed -i "s/1000/$(shuf -i 500-1500 -n 1)/g" >> output_temp done     mv output_temp original_file
  • the while loop reads each line file , replaces them.
  • mvreplaces original file temp file.

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